Optimal. Leaf size=155 \[ -\frac{\cos (c+d x)}{a^2 d}-\frac{2 \tan ^7(c+d x)}{7 a^2 d}+\frac{2 \tan ^5(c+d x)}{5 a^2 d}-\frac{2 \tan ^3(c+d x)}{3 a^2 d}+\frac{2 \tan (c+d x)}{a^2 d}+\frac{2 \sec ^7(c+d x)}{7 a^2 d}-\frac{7 \sec ^5(c+d x)}{5 a^2 d}+\frac{3 \sec ^3(c+d x)}{a^2 d}-\frac{5 \sec (c+d x)}{a^2 d}-\frac{2 x}{a^2} \]
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Rubi [A] time = 0.289752, antiderivative size = 155, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 8, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.276, Rules used = {2875, 2873, 2606, 194, 3473, 8, 2590, 270} \[ -\frac{\cos (c+d x)}{a^2 d}-\frac{2 \tan ^7(c+d x)}{7 a^2 d}+\frac{2 \tan ^5(c+d x)}{5 a^2 d}-\frac{2 \tan ^3(c+d x)}{3 a^2 d}+\frac{2 \tan (c+d x)}{a^2 d}+\frac{2 \sec ^7(c+d x)}{7 a^2 d}-\frac{7 \sec ^5(c+d x)}{5 a^2 d}+\frac{3 \sec ^3(c+d x)}{a^2 d}-\frac{5 \sec (c+d x)}{a^2 d}-\frac{2 x}{a^2} \]
Antiderivative was successfully verified.
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Rule 2875
Rule 2873
Rule 2606
Rule 194
Rule 3473
Rule 8
Rule 2590
Rule 270
Rubi steps
\begin{align*} \int \frac{\sin ^3(c+d x) \tan ^4(c+d x)}{(a+a \sin (c+d x))^2} \, dx &=\frac{\int \sec (c+d x) (a-a \sin (c+d x))^2 \tan ^7(c+d x) \, dx}{a^4}\\ &=\frac{\int \left (a^2 \sec (c+d x) \tan ^7(c+d x)-2 a^2 \tan ^8(c+d x)+a^2 \sin (c+d x) \tan ^8(c+d x)\right ) \, dx}{a^4}\\ &=\frac{\int \sec (c+d x) \tan ^7(c+d x) \, dx}{a^2}+\frac{\int \sin (c+d x) \tan ^8(c+d x) \, dx}{a^2}-\frac{2 \int \tan ^8(c+d x) \, dx}{a^2}\\ &=-\frac{2 \tan ^7(c+d x)}{7 a^2 d}+\frac{2 \int \tan ^6(c+d x) \, dx}{a^2}-\frac{\operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^4}{x^8} \, dx,x,\cos (c+d x)\right )}{a^2 d}+\frac{\operatorname{Subst}\left (\int \left (-1+x^2\right )^3 \, dx,x,\sec (c+d x)\right )}{a^2 d}\\ &=\frac{2 \tan ^5(c+d x)}{5 a^2 d}-\frac{2 \tan ^7(c+d x)}{7 a^2 d}-\frac{2 \int \tan ^4(c+d x) \, dx}{a^2}-\frac{\operatorname{Subst}\left (\int \left (1+\frac{1}{x^8}-\frac{4}{x^6}+\frac{6}{x^4}-\frac{4}{x^2}\right ) \, dx,x,\cos (c+d x)\right )}{a^2 d}+\frac{\operatorname{Subst}\left (\int \left (-1+3 x^2-3 x^4+x^6\right ) \, dx,x,\sec (c+d x)\right )}{a^2 d}\\ &=-\frac{\cos (c+d x)}{a^2 d}-\frac{5 \sec (c+d x)}{a^2 d}+\frac{3 \sec ^3(c+d x)}{a^2 d}-\frac{7 \sec ^5(c+d x)}{5 a^2 d}+\frac{2 \sec ^7(c+d x)}{7 a^2 d}-\frac{2 \tan ^3(c+d x)}{3 a^2 d}+\frac{2 \tan ^5(c+d x)}{5 a^2 d}-\frac{2 \tan ^7(c+d x)}{7 a^2 d}+\frac{2 \int \tan ^2(c+d x) \, dx}{a^2}\\ &=-\frac{\cos (c+d x)}{a^2 d}-\frac{5 \sec (c+d x)}{a^2 d}+\frac{3 \sec ^3(c+d x)}{a^2 d}-\frac{7 \sec ^5(c+d x)}{5 a^2 d}+\frac{2 \sec ^7(c+d x)}{7 a^2 d}+\frac{2 \tan (c+d x)}{a^2 d}-\frac{2 \tan ^3(c+d x)}{3 a^2 d}+\frac{2 \tan ^5(c+d x)}{5 a^2 d}-\frac{2 \tan ^7(c+d x)}{7 a^2 d}-\frac{2 \int 1 \, dx}{a^2}\\ &=-\frac{2 x}{a^2}-\frac{\cos (c+d x)}{a^2 d}-\frac{5 \sec (c+d x)}{a^2 d}+\frac{3 \sec ^3(c+d x)}{a^2 d}-\frac{7 \sec ^5(c+d x)}{5 a^2 d}+\frac{2 \sec ^7(c+d x)}{7 a^2 d}+\frac{2 \tan (c+d x)}{a^2 d}-\frac{2 \tan ^3(c+d x)}{3 a^2 d}+\frac{2 \tan ^5(c+d x)}{5 a^2 d}-\frac{2 \tan ^7(c+d x)}{7 a^2 d}\\ \end{align*}
Mathematica [A] time = 0.779097, size = 267, normalized size = 1.72 \[ -\frac{5488 \sin (c+d x)+6720 c \sin (2 (c+d x))+6720 d x \sin (2 (c+d x))-13224 \sin (2 (c+d x))+8376 \sin (3 (c+d x))+3360 c \sin (4 (c+d x))+3360 d x \sin (4 (c+d x))-6612 \sin (4 (c+d x))+2248 \sin (5 (c+d x))+42 (280 c+280 d x-551) \cos (c+d x)+14834 \cos (2 (c+d x))+2520 c \cos (3 (c+d x))+2520 d x \cos (3 (c+d x))-4959 \cos (3 (c+d x))+1852 \cos (4 (c+d x))-840 c \cos (5 (c+d x))-840 d x \cos (5 (c+d x))+1653 \cos (5 (c+d x))-210 \cos (6 (c+d x))+11172}{6720 a^2 d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^3 \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^7} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.144, size = 253, normalized size = 1.6 \begin{align*} -{\frac{1}{12\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-3}}-{\frac{1}{8\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-2}}+{\frac{1}{2\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-1}}-2\,{\frac{1}{d{a}^{2} \left ( 1+ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{2} \right ) }}-4\,{\frac{\arctan \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) }{d{a}^{2}}}+{\frac{4}{7\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-7}}-2\,{\frac{1}{d{a}^{2} \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{6}}}+{\frac{6}{5\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-5}}+2\,{\frac{1}{d{a}^{2} \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{4}}}-{\frac{1}{12\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-3}}-{\frac{23}{8\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-2}}-{\frac{9}{2\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-1}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.70179, size = 684, normalized size = 4.41 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.71709, size = 404, normalized size = 2.61 \begin{align*} -\frac{210 \, d x \cos \left (d x + c\right )^{5} + 105 \, \cos \left (d x + c\right )^{6} - 420 \, d x \cos \left (d x + c\right )^{3} - 389 \, \cos \left (d x + c\right )^{4} - 173 \, \cos \left (d x + c\right )^{2} - 2 \,{\left (210 \, d x \cos \left (d x + c\right )^{3} + 281 \, \cos \left (d x + c\right )^{4} + 51 \, \cos \left (d x + c\right )^{2} - 5\right )} \sin \left (d x + c\right ) + 25}{105 \,{\left (a^{2} d \cos \left (d x + c\right )^{5} - 2 \, a^{2} d \cos \left (d x + c\right )^{3} \sin \left (d x + c\right ) - 2 \, a^{2} d \cos \left (d x + c\right )^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.3241, size = 236, normalized size = 1.52 \begin{align*} -\frac{\frac{1680 \,{\left (d x + c\right )}}{a^{2}} + \frac{1680}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )} a^{2}} - \frac{35 \,{\left (12 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 27 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 13\right )}}{a^{2}{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1\right )}^{3}} + \frac{3780 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{6} + 25095 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 68845 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 98350 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 75222 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 29659 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 4777}{a^{2}{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}^{7}}}{840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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